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前面学习了线程基本的概念和创建线程的两种方法,现在看看多线程如何处理竞争条件(racing condition)的问题,当多个线程同时执行的时候,怎么进行控制。
比如说,下面的例子中 我使用了第二种创建的方式,自定义一个类,继承Thread类,然后自定义run()来执行我的方法。在这个run方法里面,每次都对全局变量加1
在主线程里面,他调用一个自己定义的函数,在这个函数里面创建了5000个线程;每个线程都加入一个列表,然后对每个对象都使用join,这是确保主线程等着直到所有子线程完成。最后输出结果
import timeimport threadingsome_var = 0class IncrementThread(threading.Thread): def run(self): #we want to read a global variable #and then increment it global some_var read_value = some_var print ("some_var in %s is %d" % (self.name, read_value)) some_var = read_value + 1 print ("some_var in %s after increment is %d" % (self.name, some_var))def use_increment_thread(): threads = [] start=time.time() for i in range(5000): t = IncrementThread() threads.append(t) t.start() for t in threads: t.join() print("Total time %s"%(time.time()-start)) print ("After 5000 modifications, some_var should have become 5000") print ("After 5000 modifications, some_var is %d" % (some_var,))use_increment_thread()------------------Total time 1.7780036926269531After 5000 modifications, some_var should have become 5000After 5000 modifications, some_var is 4987
可以看见结果并不是5000,这是为啥呢? 如果查看过程,会发现有些线程刚刚获取了一个值,还未来得及处理,执行的权力就转交给了另外一个线程,这样就导致计数错误。为了确保每一个线程都成功的执行了他应该执行的代码,我们可以加一把锁。
some_var in Thread-1524 is 1523some_var in Thread-1524 after increment is 1524some_var in Thread-1525 is 1524some_var in Thread-1526 is 1524some_var in Thread-1526 after increment is 1525some_var in Thread-1527 is 1525
下面是修订过的代码,通过使用Lock()函数,我们在执行代码前acquire(),之后release(),在当前线程完成这段代码之前,其他的线程不可以执行相同的操作。
some_var = 0lock=threading.Lock()class IncrementThread(threading.Thread): def run(self): #we want to read a global variable #and then increment it global some_var lock.acquire() read_value = some_var print ("some_var in %s is %d" % (self.name, read_value)) some_var = read_value + 1 print ("some_var in %s after increment is %d" % (self.name, some_var)) lock.release()def use_increment_thread(): threads = [] start=time.time() for i in range(5000): t = IncrementThread() threads.append(t) t.start() for t in threads: t.join() print("Total time %s"%(time.time()-start)) print ("After 5000 modifications, some_var should have become 5000") print ("After 5000 modifications, some_var is %d" % (some_var,))use_increment_thread()---------------Total time 1.6369926929473877After 5000 modifications, some_var should have become 5000After 5000 modifications, some_var is 5000
线程锁,除了上面的Lock()之外,还有一些常用的,比如
Rlock(),允许多重嵌套锁,而Lock()只能锁一次;
还有一个常见的是BoundedSemaphore(信标),可以指定一次锁几个
例如,我可以指定一次放行5个,30个线程分6次出来
-*- coding:utf-8 -*-import threadingimport timeNUM = 10def func(i,l): global NUM # 上锁 l.acquire() # 30,5 25m5,20 NUM -= 1 time.sleep(2) print(NUM,i) # 开锁 l.release()# lock = threading.Lock()# lock = threading.RLock()lock = threading.BoundedSemaphore(5)for i in range(30): t = threading.Thread(target=func,args=(i,lock,)) t.start()
还有一种放行的方式叫做Event(),他是统一的放行或者堵塞。
工作方式是通过一个flag的值,set()设置为True,clear()设置为False。如果flag为False,wait()则会堵塞。初始化的时候flag默认为False,即堵塞
#!/usr/bin/env python# -*- coding:utf-8 -*-# Author:Alex Liimport threadingdef func(i,e): print(i) e.wait() # 检测是什么等,如果是红灯,停;绿灯,行 print(i+100)event = threading.Event() #初始化,flag设置为False(红灯)for i in range(10): t = threading.Thread(target=func, args=(i,event,)) t.start()#========# event.clear() # 设置成红灯,可以不写,因为初始化已经实现了inp = input('>>>')if inp == "1": event.set() # 设置成绿灯-----------------0123456789>>>1100104103105107109102106101108
最后我们来看看condition(条件),我们可以灵活的设置一次放行1个或者多个线程。这些线程都hang住,直到收到notify(通知)才放行
import threadingclass t1(threading.Thread): def __init__(self,i,con): self.i=i self.con=con super(t1,self).__init__() def run(self): print(self.i) self.con.acquire() self.con.wait() print(self.i+100) self.con.release()c=threading.Condition()def test(con): for i in range(10): t=t1(i,con) t.start() while True: inp=input('>>>') if inp=='q': break con.acquire() con.notify(int(inp)) con.release()test(c)--------------0123456789>>>2>>>1001013>>>1021031044>>>105107108106
可以看见上面的代码里面,在wait()和notify()的前后都上了锁,这个锁是初始化的时候自动创建的。如果我们把他去掉,他会直接抛出异常
Traceback (most recent call last): File "C:/Users/yli/Documents/Tencent Files/38144205/FileRecv/FileRecv/day11/s6.py", line 56, intest(c) File "C:/Users/yli/Documents/Tencent Files/38144205/FileRecv/FileRecv/day11/s6.py", line 53, in test con.notify(int(inp)) File "C:\Program Files\Python3\lib\threading.py", line 343, in notify raise RuntimeError("cannot notify on un-acquired lock")RuntimeError: cannot notify on un-acquired lock
看看源码,他的确是强调只能对上锁的线程进行操作
def notify(self, n=1): """Wake up one or more threads waiting on this condition, if any. If the calling thread has not acquired the lock when this method is called, a RuntimeError is raised. This method wakes up at most n of the threads waiting for the condition variable; it is a no-op if no threads are waiting. """ if not self._is_owned(): raise RuntimeError("cannot notify on un-acquired lock") all_waiters = self._waiters waiters_to_notify = _deque(_islice(all_waiters, n))
conditon还有一种写法是wait_for,他后面参数需要传入一个函数的名字,然后他会内部调用这个函数,如果返回值为真,那么就继续,否则就等着
import threadingdef condition(): ret = False r = input('>>>') if r == 'true': ret = True else: ret = False return retdef func(i,con): print(i) con.acquire() con.wait_for(condition) print(i+100) con.release()c = threading.Condition()for i in range(10): t = threading.Thread(target=func, args=(i,c,)) t.start()---------------"C:\Program Files\Python3\python.exe" "C:/Users/yli/Documents/Tencent Files/38144205/FileRecv/FileRecv/day11/s7.py"0>>>123456789true100>>>true101>>>ksdf>>>true103>>>1>>>1>>>>>>
当我们学完conditon之后,如果回头看前面event()的源码,会发现他本质就是调用的condition,当他放行的时候,他直接放行了所有的线程;因此Event的效果是要么全部停,要么全部开通
class Event: """Class implementing event objects. Events manage a flag that can be set to true with the set() method and reset to false with the clear() method. The wait() method blocks until the flag is true. The flag is initially false. """ # After Tim Peters' event class (without is_posted()) def __init__(self): self._cond = Condition(Lock()) self._flag = False
def set(self): """Set the internal flag to true. All threads waiting for it to become true are awakened. Threads that call wait() once the flag is true will not block at all. """ with self._cond: self._flag = True self._cond.notify_all()
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